9x^2+24x+16=25

Solution for 9x^2+24x+16=25 equation:

9x^2+24x+16=25

We move all terms to the left:

9x^2+24x+16-(25)=0

We add all the numbers together, and all the variables

9x^2+24x-9=0

a = 9; b = 24; c = -9;
Δ = b2-4ac
Δ = 242-4·9·(-9)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-30}{2*9}=\frac{-54}{18}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+30}{2*9}=\frac{6}{18}
=1/3
$